The author posted a question in Homework
help me solve a physics problem please! A body falls freely from a height of 45 m. What is the path it takes during the last seconds of the fall? and got a better answer
Response from Дима[+++]
h=g*t*t/2 You count the total time of flight: t= square root of 2*h/g =3 sec Now count how much the body flew for 3-1=2 sec time before the last second , by the same formula. h=10*2*2/2=20m So the body flew 45-20=25m in the last second?
Response from 0[++]
h=g*t*t 2 You count the total time of flight: t= square root 2*h g=3 sec Now count how much the body flew for 3-1=2 sec time before the last second by the same formula. h=10*2*2 2=20 m So the body flew 45-20=25 m in the last second.
h=g*t*t 2 You count the total time of flight: t= square root 2*h g=3 sec Now count how much the body flew for 3-1=2 sec time before the last second by the same formula. h=10*2*2 2=20 m So the body flew 45-20=25 m in the last second.
Response from 0[++]
25 meters
25 meters