The author posted a question in Homework
Please help me solve 2 problems! If you help me, I will thank you and get an A for the trimester? and got a better answer
Response from Дима[+++]
Response from 0[+]
try reading the tutorial. so why would you get an "a" if you posted the problem here;
try reading the tutorial. so why would you get an "a" if you posted the problem here;
Response from 0[++]
A do you think you need? In the first problem, draw a triangle, mark points and lines for the median upward. I do not remember the cathetus, etc. Read the rules! Write down all numbers and then divide the second problem. the same thing. just read the 8th grade rule and that's it
A do you think you need? In the first problem, draw a triangle, mark points and lines for the median upward. I do not remember the cathetus, etc. Read the rules! Write down all numbers and then divide the second problem. the same thing. just read the 8th grade rule and that's it
Response from 0[+++++]
1. K is the middle of the CE. Its coordinate is -5+1 /2; 2-4 /2, or -2;-1 DK= root x D - x K ^2 + y D - y K ^2= root 6^2 + 4^2= root 60= 2*root 15 2. Equation of a straight line - y= kx + b Let's substitute the given pair of x and y in the equation and get a system:{1= -3k + b{9= -5k + b from the upper equation subtract -8= 2k k= -4 Substitute k in any of the equations 1= -3 * -4 + b b= -11 we get: y= - 4x - 11
1. K is the middle of the CE. Its coordinate is -5+1 /2; 2-4 /2, or -2;-1 DK= root x D - x K ^2 + y D - y K ^2= root 6^2 + 4^2= root 60= 2*root 15 2. Equation of a straight line - y= kx + b Let's substitute the given pair of x and y in the equation and get a system:{1= -3k + b{9= -5k + b from the upper equation subtract -8= 2k k= -4 Substitute k in any of the equations 1= -3 * -4 + b b= -11 we get: y= - 4x - 11