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Help solve a 7th grade physics problem? and got a better answer
Response from Дима[+++]
Draw a cylinder, from the bottom draw 1 cm, it is mercury, even higher - 13.6 cm - it is water with equal weight its volume is 13.6 times greater. Total height is 14.6. Divide 29.2 by 14.6 we get 2, hence we have 2 cm of mercury and 27.2 cm of water 13.6x2=27.2. Then we determine the pressure e.g.: per 1 cm2 . Mercury pressure: 13.6gx2cm=27.2g/cm2 , water pressure 1gx27.2cm=27.2g/cm2 : 54.4g/cm2?
Response from 0[+++++]
Draw a cylinder from the bottom drew 1 cm is mercury even higher - 13 6 cm is water with equal weight its volume is 13 6 times greater. Total height 14 6. Divide 29 2 by 14 6 we get 2 hence we have 2 cm of mercury and 27 2 cm of water 13 6x2=27 2. Next determine the pressure for example: per 1 sq. cm. Mercury pressure: 13 6gx2cm=27.2g cm sq. cm water pressure 1gx27 2cm=27.2g cm sq. AMOUNT: 54 4g cm sq.
Draw a cylinder from the bottom drew 1 cm is mercury even higher - 13 6 cm is water with equal weight its volume is 13 6 times greater. Total height 14 6. Divide 29 2 by 14 6 we get 2 hence we have 2 cm of mercury and 27 2 cm of water 13 6x2=27 2. Next determine the pressure for example: per 1 sq. cm. Mercury pressure: 13 6gx2cm=27.2g cm sq. cm water pressure 1gx27 2cm=27.2g cm sq. AMOUNT: 54 4g cm sq.
Response from 0[++]
tin.
tin.