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Calculate the pH of a solution if 10 liters of sulfuric acid solution is added to two liters of water? and got a better answer
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10 liters of 98 acid. maybe 10 ml? C1 H2SO4=10*w*p/M=10*98*1.84/98= mol/L after dilution C=C1*V1 / [V1+V H2O ] H2SO4=2H+ + SO42 [H+]=2C pH=-lg[H+]
Response from 0[+++++]
10 liters of 98 acid. maybe 10 ml? C1 H2SO4=10*w*p M=10*98*1 84 84= mol L after dilution C=C1*V1 [V1+V H2O ] H2SO4=2H+ + SO42 [H+]=2C pH=-lg[H+]
10 liters of 98 acid. maybe 10 ml? C1 H2SO4=10*w*p M=10*98*1 84 84= mol L after dilution C=C1*V1 [V1+V H2O ] H2SO4=2H+ + SO42 [H+]=2C pH=-lg[H+]