The author posted a question in Homework
The base of the pyramid MAVD is the square ABCD with side6 cm. The rib MB is the height of the pyramid and is equal to 8 cm. Find? and got a better answer
Response from Дима[+++]
Find the total surface area of the pyramid The base of the pyramid MABCD is a square. ABCD. side of which. 6 cm. The rib MV is the height of the pyramid. MB= 8 cm. 1Sosn=6*6=36; 2SABM=SBMS=6*8:2=24; 3 AM2 squared=CM2=6*6+8*8=100 then AM=CM=10 By the theorem of three perpendiculars MAK=90, angle DCM=90 SMAD=SMSD=6*10: 2==30; Then total surface of the pyramid is 36+24+24+30+30 = 144 sq cm
Response from 0[+++++]
Find the total surface area of the pyramid The base of the pyramid MABCD is a square. ABCD. side of which. 6 cm. The rib MB is the height of the pyramid. MB= 8 cm. 1Sosn=6*6=36; 2SABM=SBMS=6*8:2=24; 3 AM2 squared=CM2=6*6+8*8=100 then AM=CM=10 By the theorem of three perpendiculars angle MAK=90, angle DCM=90 SMAD=SMSD=6*10: 2==30; Then total surface of the pyramid is 36+24+24+30+30 = 144 sq cm
Find the total surface area of the pyramid The base of the pyramid MABCD is a square. ABCD. side of which. 6 cm. The rib MB is the height of the pyramid. MB= 8 cm. 1Sosn=6*6=36; 2SABM=SBMS=6*8:2=24; 3 AM2 squared=CM2=6*6+8*8=100 then AM=CM=10 By the theorem of three perpendiculars angle MAK=90, angle DCM=90 SMAD=SMSD=6*10: 2==30; Then total surface of the pyramid is 36+24+24+30+30 = 144 sq cm
Response from 0[+++++]
What can I find?
What can I find?