The author posted a question in Homework
help me solve an example for 6th grade I'm already brain boiling? and got a better answer
Response from Дима[+++]
Either there is a typo in the textbook or in the problem book. For an even answer, I would like to see a typo in the problem book. Look: when you put the same multiplier behind the parentheses, the first parenthesis is 3, although it should be 3.5-1.5 =2. I.e., instead of 1.5 it should be 0.5. If the error is in the problem book, then I give a more detailed example: Let's take the general multipliers out of parentheses, and consider only the numerator, because we get 0.18 in the denominator; everything is clear there: 0.5*3.5-0.5+5.5*1.7+1.3 Correspondingly, we obtain: 0.5*3+5.5*3=1.5+16.5=18. Remember, we have 0.18 in the denominator, so we get 18/0.18=100 And if there is a mistake in the rehearsal book, the answer will not be so pretty: 0.5*3.5-1.5 +5.5*1.7+1.3 = 0.5*2+5.5*3=1+16.5=17.5; 17.5/0.18=97 2 i.e. 97 and 2 in the period?
Either there's a typo in the book or in the problem book. For an even answer, I would like the typo to be in the problem book. See: when you put the same multiplier in the first parenthesis is 3 although it should be 3.5-1.5 = 2. Ie instead of 1.5 should be 0.5. If the error in the problem book I give a more detailed example: Let's take the general multipliers out of parentheses, we consider only the numerator, because we get 0.18 in the denominator: 0.5* 3.5-0.5 +5.5* 1.7+1.3 Correspondingly we get: 0.5*3+5.5*3=1.5+16.5=18. Remember, we have 0.18 in the denominator, so we get 18 0.18=100. And if you make a mistake in the formula, the answer will not be as beautiful: 0.5*3.5-1.5 +5.5*1.7+1.3= 0.5*2+5.5*3=1+16.5=17.5; 17.5=0.18=97 2, so 97 and 2 in the period
explain the matrix and derivatives to him.
but just explain that first we multiply everything at the top, then we add, then we multiply everything at the bottom, then we add, then we subtract, and finally we divide by each other?
We take 0 5 from the first pair of brackets in the numerator and 5 5 5 from the second pair, and then we take 0 3 in the denominator and find the values inside the brackets, and then as written
It is necessary to group the summands and take the common multiplier out of the brackets. But I don't like it - either the condition is wrongly written off or the answer is wrongly written off. And what is the answer in the numerator after 5 5 * 3 plus or multiply or what? And the condition in the denominator wants a plus, not a minus.
I don't get 100 First simplify then calculate 0 5* 3 5-1 5 + 5 5* 1 7+1 3 0 3* 0 8-0 2= 0 5*2 +5 5*3 0 3*0 6= 1+16 5 0 18=? Did you write the example down correctly?
you must have a typo, it's not 3 5*05-1 5*0 5 at the top, it's 3 5*0 5-0 5*0 5. You get 0 5* 3 5-0 5 +5 5* 1 7+1 3 and you get 0 5*3+5 5*3 you get 3* 0 5+5 5 you get 3*6. You get 0 3* 0 8-0 2 you get 0 3*0 6. So 3 is 10 times bigger than 0.3 and 6 is 10 times bigger than 0.6. 10*10 is 100.
You have something wrong with your condition see: Numerator: 3.5*0.5-1.5*0.5+5.5*1.7+5.5*1.3= 0.5* 3.5-1.5 +5.5* 1. 7+1.3= 0.5*2+5.5*3=1+16.5=17.5 Denominator 0.3*0.8-0.3*0.2=0.3* 0.8-0.2= 0.3*0.8=0.16 All expression: 17.5 0.18=100*17.5 18=97.2222222