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the roots of a cubic equation? and got a better answer
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What's the question?
What's the question?
Response from 0[+++++]
Searchable By the Bezos theorem.is when one of the roots of an equation is a number multiple of the free term!
Searchable By the Bezos theorem.is when one of the roots of an equation is a number multiple of the free term!
Response from 0[+]
Bezu is for multiples of 2, for cubic - Cardano
Bezu is for multiples of 2, for cubic - Cardano
Response from 0[+++++]
First substitute 1 or -1 or another small number. One of those will do. This is the first root. Then divide the equation by the unknown minus the root. The partial will be a quadratic equation, and it is easy to solve. For example: x^3 - 2x^2 - 5x + 6=0 x=1 x^3 - 2x^2 - 5x + 6 / x-1= x^2 - x - 6 column division x=2 x=-3
First substitute 1 or -1 or another small number. One of those will do. This is the first root. Then divide the equation by the unknown minus the root. The partial will be a quadratic equation, and it is easy to solve. For example: x^3 - 2x^2 - 5x + 6=0 x=1 x^3 - 2x^2 - 5x + 6 / x-1= x^2 - x - 6 column division x=2 x=-3