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Response from Дима[+++]
the mass of potassium sulfate = 1422*0.045=63.99=64 g the mass of sulfuric acid that has reacted = 64*98/194=32.33 g the mass of sulfuric acid in the initial solution 394*0.05=19.7 g the mass of sulfuric acid obtained from sulfur trioxide 32.33-19.7=12.63 g the mass of dissolved trioxide = 12.63*80/98=10.31 g?
Response from 0[+++++]
mass of potassium sulfate = 1422*0 045=63 99=64 g mass of sulfuric acid reacted = 64*98 194=32 33 g mass of sulfuric acid in initial solution 394*0 05=19 7 g mass of sulfuric acid obtained from sulfur trioxide 32 33-19 7=12 63 g mass of dissolved trioxide = 12 63*80 98=10 31 g
mass of potassium sulfate = 1422*0 045=63 99=64 g mass of sulfuric acid reacted = 64*98 194=32 33 g mass of sulfuric acid in initial solution 394*0 05=19 7 g mass of sulfuric acid obtained from sulfur trioxide 32 33-19 7=12 63 g mass of dissolved trioxide = 12 63*80 98=10 31 g