The author posted a question in Homework
Easy problem? and got a better answer
Response from Дима[+++]
Good logical problem! On day 1 -x, on day 2 x+a, On day 3 x+v, c>a; on day 4 - 4x. Const. equation: x + x + a + x + b +4x = 23; 7x = 23 a + c; the nearest number to 23, a multiple of 7 is 14 21 does not fit, because a does not equal in So, 7x = 14, x = 2; a + c = 23 -14 = 9 So, on day 1, he solved 2 problems, in the 4th - 8 problems, in the 2nd - 2 + 4 = 6 problems, in the 4th - 4 + 5 = 7?
Response from 0[+++++]
Good logical problem! On day 1 -x on day 2 x+a On day 3 x+v in>a; on day 4 - 4x. Thus, the equation: x + x + a + x + b + 4 x = 23; 7 x = 23 a + c; the nearest number to 23 is a multiple of 7 - it is 14 21 not valid, because a is not equal to c So 7 x = 14 x = 2; a + c = 23 -14 = 9 So, on day 1 he had 2 problems on day 4 - 8 problems on day 2 - 2 + 4 = 6 problems on day 4 - 4 + 5 = 7.
Good logical problem! On day 1 -x on day 2 x+a On day 3 x+v in>a; on day 4 - 4x. Thus, the equation: x + x + a + x + b + 4 x = 23; 7 x = 23 a + c; the nearest number to 23 is a multiple of 7 - it is 14 21 not valid, because a is not equal to c So 7 x = 14 x = 2; a + c = 23 -14 = 9 So, on day 1 he had 2 problems on day 4 - 8 problems on day 2 - 2 + 4 = 6 problems on day 4 - 4 + 5 = 7.
Response from 0[++++]
let the first day be x. Then the second day will be.
let the first day be x. Then the second day will be.