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VERTEX C OF A TRAPEZOID OABC LIES ON THE POSITIVE SEMIAXIS OX OC=10 AB=6 VERTEX? and got a better answer

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DON'T YELL HERE!

**0**[+++++]DON'T YELL HERE!

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AA1 and BB1 are the heights of the trapezoid on the OS base=&gt; Point M lies in the IY quarter and has coordinates: along the OY axis -&gt; y M= AA12 &lt; 0 along the OX axis -&gt; x M= 0 + OA12 &gt; 0 Point N is also in the IY quarter respectively: along the OY axis -&gt; y N= BB12= AA12 &lt; 0 along the OX axis -&gt; x N= OC - B1C2 The assignment does not say that OA= BC. The height of OABC is also not specified. Length MN= OC + AB 2= 10 + 6 2= 8 It follows that OA1 + B1C= 10 - 6= 4 The exact coordinates of M and N cannot be determined more precisely from the given data.

**0**[+++++]AA1 and BB1 are the heights of the trapezoid on the OS base=&gt; Point M lies in the IY quarter and has coordinates: along the OY axis -&gt; y M= AA12 &lt; 0 along the OX axis -&gt; x M= 0 + OA12 &gt; 0 Point N is also in the IY quarter respectively: along the OY axis -&gt; y N= BB12= AA12 &lt; 0 along the OX axis -&gt; x N= OC - B1C2 The assignment does not say that OA= BC. The height of OABC is also not specified. Length MN= OC + AB 2= 10 + 6 2= 8 It follows that OA1 + B1C= 10 - 6= 4 The exact coordinates of M and N cannot be determined more precisely from the given data.