The author posted a question in Homework
Physics problem! HELP you solve it? and got a better answer
Response from Дима[+++]
The tension of the threads has not changed, so the gravity force mg is equal to the pushing force of the square ball see figure: F= pgv-mg, where p is the density of water, g is the acceleration of free fall, v,m are the volume and mass of the ball. Now we equate the two forces: mg= pgv - mg pgv= 2mg pv=2m p/2= m/v= P density of the ball: P=m/v That is the density of the ball is half the density of water
Response from 0[++]
The tension of the threads has not changed, so the force of gravity mg is equal to the pushing force of the square ball see figure: F= pgv-mg where p is the density of water g is the acceleration of gravity v m is the volume and mass of the ball. Now let's equate the two forces: mg= pgv - mg pgv= 2mg pv= 2m p 2= m v= P density of the ball: P=m v That is the density of the ball is half the density of water
The tension of the threads has not changed, so the force of gravity mg is equal to the pushing force of the square ball see figure: F= pgv-mg where p is the density of water g is the acceleration of gravity v m is the volume and mass of the ball. Now let's equate the two forces: mg= pgv - mg pgv= 2mg pv= 2m p 2= m v= P density of the ball: P=m v That is the density of the ball is half the density of water