The author posted a question in Homework
People, help solve an inequality in algebra? and got a better answer
Response from Дима[+++]
Response from 0[+++++]
Subordinate expression >0 from 0 to 7 Denominator from -3 to 3 their intersection gives 0<=x<3 or [0;3 At 3 the denominator is 0 and cannot be divided by zero.
Subordinate expression >0 from 0 to 7 Denominator from -3 to 3 their intersection gives 0<=x<3 or [0;3 At 3 the denominator is 0 and cannot be divided by zero.
Response from 0[+++++]
stupidly determine the definition areas of the function i.e. 7x-x^2 >=0 and 9-x^2 is not equal to 0 - i.e. the range where the function values exist then find the roots 7x-x^2=0 and 9-x^2= 0 have determined the intervals of the familiar constant substitute values into the equation select intervals where the equation takes positive values solve the whole equation in this case is not necessary
stupidly determine the definition areas of the function i.e. 7x-x^2 >=0 and 9-x^2 is not equal to 0 - i.e. the range where the function values exist then find the roots 7x-x^2=0 and 9-x^2= 0 have determined the intervals of the familiar constant substitute values into the equation select intervals where the equation takes positive values solve the whole equation in this case is not necessary
Response from 0[+]
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Response from 0[+++++]
Solve the system 7x -x^2 greater than or equal to 0 9x^2 greater than 0 Solution of the first is an interval from 0 to 7 and solution of the second is an interval -3; 3. Solve the system from 0 including 0 to 3.
Solve the system 7x -x^2 greater than or equal to 0 9x^2 greater than 0 Solution of the first is an interval from 0 to 7 and solution of the second is an interval -3; 3. Solve the system from 0 including 0 to 3.