Explain how to solve: x^3 x^2 =-2 ^-degree.



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Explain how to solve: x^3 x^2 =-2 ^-degree. and got a better answer

Response from Дима[+++]
x^3-x^2+2=0 x^3-x^2+1+1=0 x^3+1 x^2-1=0 by the reduced multiplication formulas we get x+1 x^2-x-1 x-1 x+1=0 x+1 x^2-x-1-x+1=0 x+1 x^2+1=0 x+1=0 or x^2+1=0 x+1=0 x^2=-1 no roots X=-1?

Response from 0[+++++]
x^3-x^2+2=0 x^3-x^2+1+1=0 x^3+1 x^2-1=0 x+1 x^2-x-1 x+1=0 x+1 x^2-x-1 x+1=0 x+1 x^2-x-1-x+1=0 x+1+1 x^2+1=0 x+1=0 or x^2+1=0 x+1=0 x^2=-1 no roots X=-1

Response from 0[+++++]
x^3-x^2+2=0 choose all the divisors of 2 is: 1 -1 2 -1. Find the root of x=-1 by substituting it into the equation. Then the equation is divided by x+1 and we get x^2-2x+2. The quadratic equation is also equated to 0.x^2-2x+2=0 and solved through the discriminant: D=2^2-4*1*2=-2 - no solution. Answer: x=-1

 

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