The author posted a question in Homework
solve the problem? and got a better answer
Response from Дима[+++]
That's one big caterpillar! Are bugs and spiders all handicapped?
Response from 0[+]
That's one big caterpillar! And bugs and spiders are all handicapped.
That's one big caterpillar! And bugs and spiders are all handicapped.
Response from 0[+++++]
beetles - x spiders - y 6x+8u=54 x+u=8 multiply the second equation by 6x+6u=48 from the first: 6x=54-8u from the second: 6x=48-6u ie 54-8u=48-6u 54-48=6u+8u 6=2u y=3 hence x=5 beetles 5 spiders 3
beetles - x spiders - y 6x+8u=54 x+u=8 multiply the second equation by 6x+6u=48 from the first: 6x=54-8u from the second: 6x=48-6u ie 54-8u=48-6u 54-48=6u+8u 6=2u y=3 hence x=5 beetles 5 spiders 3
Response from 0[+]
5 beetles and 3 spiders Just need to solve the system: 6x+8y=54 x+y=8
5 beetles and 3 spiders Just need to solve the system: 6x+8y=54 x+y=8
Response from 0[+++++]
A beetle has 6 legs a spider has 8.If there were only one beetle in the box they would have 48 legs. The extra 6 legs are spider legs. And since a spider has two more legs than a beetle, 6:2=3 spiders. 8-3=5 beetles.
A beetle has 6 legs a spider has 8.If there were only one beetle in the box they would have 48 legs. The extra 6 legs are spider legs. And since a spider has two more legs than a beetle, 6:2=3 spiders. 8-3=5 beetles.
Response from 0[+++++]
There are 7 beetles and 2 six-legged spiders:
There are 7 beetles and 2 six-legged spiders: