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A carno-thermal machine? and got a better answer
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kpc= 1 - T/T= 1 - 300/500= 0.4 t. kpc= 1 - L/Q, hence Q= L/ kpc -1= 1000/0.6= 1667 J
kpc= 1 - T/T= 1 - 300/500= 0.4 t. kpc= 1 - L/Q, hence Q= L/ kpc -1= 1000/0.6= 1667 J