The author posted a question in Homework
problem from 1-7 urgently who remembers.plz.plz? and got a better answer
Response from Дима[+++]
1. By the formulas we find: t1= 140-150/10=-1 t2= 170-150 /10=2 Then: P 140<150<170=0.5 F t2 -F t1=0.5 F 2 +F 1=0.5 0.9545+0.6827=0.8186 2. M X=4*0.3+6*0.2+8*0.4+10*0.1=5.04 M X^2=16*0. 3+36*0.2+64*0.4*100*0.1=47.6 D X=47.6-5.04^2=22.1984 c.s. deviation=root their D X=4.71?
Response from 0[+++++]
1. By the formulas we find: t1= 140-150 10=-1 t2= 170-150 10=2 Then: P 140<150<170=0.5 F t2 -F t1=0.5 F 2 +F 1=0 5 0 9545+0 6827=0 8186 2. M X=4*0 3+6*0 2+8*0 4+10*0 1=5 04 M X^2=16*0. 3+36*0.2+64*0.4*100*0.1=47.6 D X=47.6-5.04^2=22.1984 RMS deviation=root their D X=4 71
1. By the formulas we find: t1= 140-150 10=-1 t2= 170-150 10=2 Then: P 140<150<170=0.5 F t2 -F t1=0.5 F 2 +F 1=0 5 0 9545+0 6827=0 8186 2. M X=4*0 3+6*0 2+8*0 4+10*0 1=5 04 M X^2=16*0. 3+36*0.2+64*0.4*100*0.1=47.6 D X=47.6-5.04^2=22.1984 RMS deviation=root their D X=4 71
Response from 0[+++++]
I don't remember that
I don't remember that