The author posted a question in Homework
Prove that tangents to intersecting circles are equal? and got a better answer
Response from
Let O and Q be centers of circles, A and B be their intersection points, M be the exit point of the tangents, MC and MD be tangents to circles with centers O and Q. By the function connecting tangent and secant we have for the circle with center O CM^2=MA*MB. Similarly, DM^2=MA*MB, so DM^2=CM^2, i.e. DM=CM, h.e.?
Response from 0[+++++]
Let O and Q be the centers of circles A and B and their intersection points M be the exit point of the tangents MC and MD are the tangents to the circles with centers O and Q. According to the tangent and secant relation we have for the circle with center O CM^2=MA*MB. Similarly DM^2=MA*MB so DM^2=CM^2 i.e. DM=CM etc.
Let O and Q be the centers of circles A and B and their intersection points M be the exit point of the tangents MC and MD are the tangents to the circles with centers O and Q. According to the tangent and secant relation we have for the circle with center O CM^2=MA*MB. Similarly DM^2=MA*MB so DM^2=CM^2 i.e. DM=CM etc.