The author posted a question in Homework
need help with algebra? and got a better answer
Response from
x^2 x^2-3 ^2 - 4 x^2-3=0 x^2-3 * x^2 x^2-3 -4=0 we get a set: x^2-3=0 or x^4-3*x^2-4=0 solve the third equation as bi-squared and get that x^2=4=> x=+-2 or x^2=-2 does not satisfy the condition and from the first equation it is obvious that the roots +-root square of three answer: +-2,roots +-root square of 3?
Response from 0[+++++]
x^2 x^2-3 ^2 - 4 x^2-3=0 x^2-3 * x^2 x^2-3 -4=0 get the aggregate: x^2-3=0 or x^4-3*x^2-4=0 solve the third equation as bi-squared and get that x^2=4=> x=+-2 or x^2=-2 does not satisfy the condition and from the first equation it is obvious that roots +-root square of three answer: +-2 roots +-root square of 3
x^2 x^2-3 ^2 - 4 x^2-3=0 x^2-3 * x^2 x^2-3 -4=0 get the aggregate: x^2-3=0 or x^4-3*x^2-4=0 solve the third equation as bi-squared and get that x^2=4=> x=+-2 or x^2=-2 does not satisfy the condition and from the first equation it is obvious that roots +-root square of three answer: +-2 roots +-root square of 3
Response from 0[++]
Wait a second. now.
Wait a second. now.